The semi circular ring of radius R and mass m is free to rotate about the point O in shown figure.

Options

A. Tension in the string is `(mg)/(2)`
B. Angular acceleration of the semi circular ring just after we cut the string is `(g)/(4R)`
C. Force due to hinge on the semi circular ring always has non zero vetical component
D. Acceleration of centre of mass of the semi circular ring, just after we cut the string, must have horizontal `&` vertical non zero components.

Explanation

(A) `Txx(R)/(2)=Mgxx(R)/(2)`
(B) `Mgxx(R)/(2)=(2MR^(2))alpha`
(D) Centre of mass tangential acceleration only.