A uniform rod of length 1m lies on the smooth part of a horizontal surface as shown. Calculate the minimum veloctiy `V_(0)` in m/s so that the rod can reach the rough surface completely. Take `g=10m//s^(2)` and coefficient of friction between the rod and the rough surface as 0.1.

Explanation

Work done by friction
`int_(L)^(0)(mumgx)/(L)dx=(mumgL)/(2)`
`therefore (1)/(2)mv_(0)^(2)=(mu mgL)/(2)`
`rArrv_(0)=sqrt(mugL)=1m//s`