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Power radiated by a black body is P0 and...

Power radiated by a black body is `P_0` and the wavelength corresponding to maximum energy is around `lamda_0`, On changing the temperature of the black body, it was observed that the power radiated becames `(256)/(81)P_0`. The shift in wavelength corresponding to the maximum energy will be

A

`(+lambda_(0))/(4)`

B

`(+lambda_(2))/(2)`

C

`-(lambda_(0))/(4)`

D

`-(lambda_(0))/(2)`

Text Solution

Verified by Experts

According to wien's law, `lambda_(0)T_(0)=lambdaT`
According to stefan's law, `(P_(0))/(P)=[(T_(0))/(T)]^(4)`
Now, `(P)/(P_(0))=(256)/(81)=[(4)/(3)]^(4)`
`therefore (T_(0))/(T)=(3)/(4)=(lambda)/(lambda_(0))`,
or `lambda=(3)/(4)lambda_(0)`
wavelength shift `Deltalambda=lambda-lambda_(0)=(3)/(4)lambda_(0)-lambda_(0)`
`=-(lambda_(0))/(4)`
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