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When the load on a wire is increasing sl...

When the load on a wire is increasing slowly from 2kg to 4kg, the elongation from 0.6mm to 1.2mm. The work done during this extension of the wire is `(g=10m//s^(2))`

A

`14xx10^(-3)J`

B

`0.4xx10^(-3)J`

C

`8xx10^(-2)J`

D

`1.8xx10^(-2)J`

Text Solution

Verified by Experts

From Hookes law
`F=(AY//L)xx x` should be valid.
`W=(1//2)(AY//L)(x_("final")^(2)-x_("initial")^(2))`
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