nA small block is given a velocity v along the inclined palne in the downward direction at the highest point on an inclined plane in the downward direction at the highest point on an inclined plane. Then block moves with constant velocity. After reaching at lowest point, block is given same speed v up the incline. find time to reach the block again at lowest point (Assume `vle2sqrt(gl sin theta)`)

Options

A. `(2l)/(v)`
B. `(l)/(2v)`
C. `(l)/(g sin theta)`
D. it will not return

Explanation

Fopr motion down the plane
`mg sin theta=f`
When block is projected up the plane. It will stop at some point. At that moment v=0 and net-acceleration along the plane will be zero so it will not return.