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A particle excuting SHM has equation y=A...

A particle excuting SHM has equation `y=A sin(omegat+(pi)/(6))` where `omega=(2pi)/(T)`, then find the possible time t when it is at `y=-(A)/(2)`

A

`(T)/(2)`

B

`(5T)/(6)`

C

`(3T)/(2)`

D

`(11T)/(6)`

Text Solution

Verified by Experts

`t_(1)=(pi)/((2pi//T))=(T)/(2)`
`t_(2)=(n+(2pi)/(3))/((2pi)/(T))=(5piT)/(6pi)=(5T)/(6)`

`t_(3)=t_(1)+T=(T)/(2)+T=(3T)/(2)`
`t_(4)=t_(2)+T=(5T)/(6)+T=(11T)/(6)`
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