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A rod of mass 1kg and length 6.25 m is h...

A rod of mass 1kg and length 6.25 m is hinged at one end of a smooth horizontal surface. A force of magnitude `(pi)/(3)N` acts it such that it is always perpendicular to the rod. Find the time (in sec.) when the rod has rotated one revolution?

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`Fl=(ml^(2))/(3)alpha`

`2pi=(1)/(2)alphat^(2)`
`t=sqrt((4pi)/(alpha))=sqrt((4piml)/(3F))`
`=sqrt((4pixx1xx6.25)/(3xx(pi)/(3)))=5sec.`
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