STATEMENT-1: The values of `f(x) = 3sin(sqrt(pi^2/16-x^2)` lie in the interval `[0,3/sqrt3]`. and STATEMENT-2 The domain of definition of the function `f(x)=3sin(sqrt(pi^2/16-x^2)` is `[-pi/4,pi/4]` .

STATEMENT-1: The values of f(x)=3sin(sqrt((pi^(2))/(16)-x^(2)) lie in the interval [0,(3)/(sqrt(3))]. and STATEMENT-2The domain of definition of the function f(x)=3sin(sqrt((pi^(2))/(16)-x^(2)) is [-(pi)/(4),(pi)/(4)]

The value of f(x)=3sin sqrt(((pi^(2))/(16)-x^(2))) lie in the interval

The value of f(x)=3cos(sqrt ((pi^2)/(16)-x^2)) lie in the interval____

The values of f(x)=3 sin(sqrt((pi^(2))/(16)-x^(2))) lie in the inerval ________

Find the range of f(x) = 3 sin sqrt(pi^2/16 - x^2) .

The domain of definition of the function f(x)=sqrt(3-2^(x)-2^(1-x))+sqrt(sin^(-1)x) is

The domain of definition of the function f(x)=sqrt(3-2^(x)-2^(1-x))+sqrt(sin^(-1)x) is

The domain of definition of the function f(x)=sqrt(3-2^(x)-2^(1-x))+sqrt(sin^(-1)x) is

Find the range of the function f(x)=3 sin (sqrt((pi^(2))/(16)-x^(2))).