The median AD of the triangle ABC is bisected at E and BE meets AC at F. Find AF:FC.

The median AD of triangle ABC is bisected at F and BF is produced to meet the side AC in P. If AP=lambda AC then what is the value of lambda

The median AD of a triangle ABC is bisected at F, and BF is produced to meet the side AC in P. If AP = lamdaAC , then what is the value of lamda .?

the median AB of Delta ABC is bisected at Eand BE is produced to meet the side AC in f.then the ratio AF:FC=

The side BC of a triangle ABC is bisected at D;o is any point in AD,BO and CO produced meet AC and AB in E and F respectively and AD is produced to X so that D is the mid-point of OX. Prove that AO:AX=AF:AB and show that FE|BC.

The median BD of the triangle ABC meets AC at D. If BD = 1/2AC , then which one of the following is correct ?

AD is a median of triangleABC . The bisectors of angleADB and angleADC meets AB and AC in E and F respectively prove that EF||BC.

The base BC of a triangle ABC is bisected at the point (a, b) and equation to the sides AB and AC are respectively ax+by=1 and bx+ay=1 Equation of the median through A is: