For a hypothetical reaction `aA + bB rarr` Product, the rate law is: rate `= K[A]^(x)[B]^(y)`, then

The rate and mechamical reaction are studied in chemical kinetics. The elementary reactions are single step reaction having no mechanism. The order of reaction and molecularity are same for elementary reactions. The rate of forward reaction aA + bBrarr cC+dD is given as: rate =((dx)/(dt))=-1/a(d[A])/(dt)=-1/b(d[B])/(dt)=1/c(d[C])/(dt)=1/d(d[D])/(dt) or expression can be written as : rate =K_(1)[A]^(a)[B]^(b)-K_(2)[C]^(c )[D]^(d) . At equilibrium, rate = 0 . The constants K, K_(1), K_(2) are rate constants of respective reaction. In case of reactions governed by two or more steps reaction mechanism, the rate is given by the slowest step of mechanism. For a hypothetical reaction aA+bBrarr Product, the rate law is: rate =K[A]^(x)[B]^(y) , then:

For a hypothetical reaction: A+B rarr Products, the rate law is r = k[A][B]^(0) . The order of reaction is

For a hypothetical reaction: A+B rarr Products, the rate law is r = k[A][B]^(0) . The order of reaction is

For a hypothetical reaction, A + B + C to Products, the rate law is determined to be rate = k[A][B]^(2) . If the concentration of B is doubled without changing the concentration of A and C, the reaction rate:

For a hypothetical reaction, A + B + C to Products, the rate law is determined to be rate = k[A][B]^(2) . If the concentration of B is doubled without changing the concentration of A and C, the reaction rate:

For a reaction pA + qB rarr Product, the rate law expresison is r = k[A][B]^(m) . Then

For a reaction pA +qB rarr products, the rate law expression is r=k[A]^(l)[B]^(m) then

For a reaction pA +qB rarr products, the rate law expression is r=k[A]^(m)[B]^(n) then

For a reaction pA + qB rarr Product, the rate law expresison is r = k[A][B]^(m) . Then