In acidic medium, the rate of reaction between `BrO_(3)^(ɵ)` and `Br^(ɵ)` is given by the expresison
`(-d[BrO_(3)^(ɵ)])/(dt) =k[BrO_(3)^(ɵ)][Br^(ɵ)][H^(o+)]^(2)`

In acidic medium, the rate of reaction between BrO_(3)^(ɵ) and Br^(ɵ) is given by the expression (-d[BrO_(3)^(ɵ)])/(dt) =k[BrO_(3)^(ɵ)][Br^(ɵ)][H^(o+)]^(2)

In acidic medium the rate of reaction between [BrO_(3)^(-)] and [Br^(-)] ions given by the expression - (d[BrO_(3)^(-)])/(dt) = k [BrO_(3)^(-)][Br^(-)][H^(+)]^(2) It means (i) rate of constant of the reaction depends upon the concentration of H^(+) ions (ii) rate of reaction is independent of the concentration of acid added (iii) the change in pH of the solution will affect the rate of reaction (iv) doubling the concentration of H^(+) ions will increase the reactions rate by 4 items.

In acidic medium, the rate of reaction between [BrO_(3)^(-)]and Br^(-) ions is given by the expression -(d[BrO_(3)^(-)])/(dt)=k[BrO_(3)^(-)][Br^(-)][H^(+)]^(2) It means

In acidic medium the rate of reaction between (BrO_(3))^(-) and Br^(-) ions is given by the expression -(d(BrO_(3)^(-)))/(dt)=k[BrO_(3)^(-)][Br^(-)][H^(+)]^(2) it means

In acidic medium the rate of reaction between (BrO_3)^- and Br^- ions is given by the expression. -(d(BrO_3^-))/dt=K[BrO_3^-][Br^-][H^+]^2 It means: