In a game a coin is tossed `2n+m` times and a player wins if he does not get any two consecutive outcomes same for at least `2n` times in a row. The probability that player wins the game is `(m+2)/(2^(2n)+1)` b. `(2n+2)/(2^(2n))` c. `(2n+2)/(2^(2n+1))` d. `(m+2)/(2^(2n))`

(m^(2)-n^(2))^(2)+2m^(2)n^(2)

Two players P_1a n dP_2 play a series of 2n games. Each game can result in either a win or a loss for P_1dot the total number of ways in which P_1 can win the series of these games is equal to a. 1/2(2^(2n)-^ "^(2n)C_n) b. 1/2(2^(2n)-2xx^"^(2n)C_n) c. 1/2(2^n-^"^(2n)C_n) d. 1/2(2^n-2xx^"^(2n)C_n)

If (m+n)/(m-n)=7/3 then (m^2-n^2)/(m^2+n^2)=

The arithmetic mean of 1,2,3,...n is (a) (n+1)/(2) (b) (n-1)/(2) (c) (n)/(2)(d)(n)/(2)+1

A coin is tossed 2n xx.The chance that the number of xx one gets head is not equal to the number of xx one gets tails is ((2n!))/((n!)^(2))((1)/(2))^(2n) b.1-((2n!))/((n!)^(2))c1-((2n!))/((n!)^(2))(1)/((4^(n))) d.none of these

Evaluate : (a^(2n+1) xx a^((2n+1)(2n-1)))/(a^(n(4n-1)) xx (a^2)^(2n+3)

((2^(m))/(2^(n)))^(t)xx((2^(n))/(2^(t)))^(m)xx((2^(t))/(2^(m)))^(n) is equal to