Simplify `(3^(-5)times5^(-7)times(-2)^(3))/(3^(4)times5^(-2)times(-2)^(-3))`

Simplify (-4)^2 times (-3) times (-5)^2

((5^(3))^(-2)times(5^(2))^(-3)times(6)^(5))/((2)^(3)times(3)^(2)times(5)^(5))

Simplify : ((-1)^5 times (-3)^3)/(4^(-2) times (-2)^5)

A real number (2^(2)times3^(2)times7^(2))/(2^(2)times5^(3)times3^(5)times7^(4)) will have

solve it : (ii) (-3)/(5)times(-3)/(5)times(-3)/(5)times(-3)/(5) (iii) (-9)/(2)times(4)/(2)times(-4)/(2)times(-4)/(2)times(-4)/(2)times(-4)/(2) (iv) (-5)/(3)times(-5)/(3)times(-5)/(3)times(-5)/(3) (v) (-6)/(2)times(-6)/(2)times(-6)/(2)times(-6)/(2)times(-6)/(2)

((2)/(3))^(4)times((3)/(2))^(5)times((5)/(3))^(-2)times((3)/(5))^(-3)

Simplify: (-5)^(2)xx(-3)^3

Simplify -(2)/(3)times5(1)/(2)times2times7(5)/(6)times(9)/(11)

[((-2)/(-3))times(1)/(5)]times((-2)/(7))=((-2)/(-3))times[(1)/(5)times((-2)/(7))]

Proved that (2)/(3)times[(-6)/(7)times(4)/(5)]=[(2)/(3)times(4)/(5)]times((-6)/(7))