The photon radiated from hydrogen corresponding to the second line of Lyman series is absorbed by a hydrogen like atom X in the second excited state. Then, the hydrogen-like atom X makes a transition of nth orbit.

The photon radiated from hydrogen corresponding to 2^(nd) of Lyman series is abosorbed by a hydrogen like atom 'X' in 2^(nd) excited state. As a result the hydrogen like atom 'X' makes a transition to n^(th) orbit. Then :

The photon radiated from hydrogen corresponding to 2^(nd) of Lyman series is abosorbed by a hydrogen like atom 'X' in 2^(nd) excited state. As a result the hydrogen like atom 'X' makes a transition to n^(th) orbit. Then :

The energy corresponding to second line of Balmer series for hydrogen atom will be:

The energy corresponding to second line of Balmer series for hydrogen atom will be :-

The wavelength of the first line of the Lyman series of a hydrogen like ion X is identical to that of the second line of the baimer series of another hydrogen like ion Y . Find the ratio of their atomic number.

The wavelength of the first line of the Lyman series of a hydrogen like ion X is identical to that of the second line of the baimer series of another hydrogen like ion Y . Find the ratio of their atomic number.

The ratio of the energy of hydrogen atom in its first excited to second excited state is

The wavelength of the first line of Lyman series for hydrogen is identical to that of the second line of Balmer series for some hydrogen like ion x. Calculate the atomic no of ion

As an electron makes a transition from an excited state to the ground state of hydrogen-like atom // ion: