`(9/4)^(1/4)xx(125/27)^(1/6)-:(625/16)^(1/8)=1`

Simplify sqrt(25)/(64)^(1/3)+(256/625)^(-1/4)+1/(64/125)^(2/3)

{(125)^(-2)xx(16)^(-3/2)}^(-1/6)=

Simplify : ((8)/(27))^(-1//3)xx((25)/(4))^(1//2)xx((4)/(9))^(0)+((125)/(64))^(1//3)

{(81)^(-3/4)xx((16)^(1/4))/(6^(-2))xx(1/27)^(-4/3)}^(1/3)=

((16)^((1)/(4)))/((27)^((1)/(3)))+((625)^((1)/(4)))/((81)^((1)/(4)))-(1)/((243)^((1)/(5)))=2

Show that 3^(1//2).9^(1//4). (27)^(1//8). (81)^(1//16)… oo = 9

Simplify: 1/(27)^(-1/3)+1/(625)^(-1/4)

Simplify: ((6.25)^(1/2) xx (0.0144)^(1/2)+ 1)/((0.027)^(1/3)xx (81)^(1/4))

(3125^(x)xx5^(9))/(625)=(125)^(-1)

If x=9^(1//3)xx9^(1//9)xx 9^(1//27)xx….,y=4^(1//3)xx-4^(1//9)xx 4^(1//27)x…., and z=Sigma_(r=1)^(oo) (1+i)^(r) then arg (x+yz) is equal to