A force exerts an impulse Ion a particle changing its speed from initial velocity `u` to final velocity `2u`. The applied force and the initial velocity are oppositely oriented along the same line. The work done by the force is

A force exerts an impulse I on a particle changing its speed from u to 2u. The applied force and the initial velocity are oppositely directed along the same line. The work done by the force is

A force exerts an impulse I on a particle changing its speed from u to 2u. The applied force and the initial velocity are oppositely directed along the same line. The work done by the force is

A force exerts an impulse J on a body changing its speed from u to upsilon . The force and object's motion are along the same line. Show that the work done by the force is J(u+upsilon)//2

Certain force acting on a 20 kg mass changes its velocity from 5m//s to 2m//s . calculate the work done by the force.

Certain force acting on a 20 kg mass changes its velocity from 5m//s to 2m//s . calculate the work done by the force.

If a particle with a = kv^(2) and initial velocity is u then velocity after S displacement. Here k is a constant

If a particle with a = kv^(2) and initial velocity is u then velocity after S displacement. Here k is a constant

Statement - 1: A particle moves along a straight line with constant velocity. Now a constant non-zero force is applied on the particle in direction opposite to its initial velocity. After the force is applied, the net work done by this force may be zero in certain time intervals. Statement - 2 : The work done by a force acting on a particle is zero in any time interval if the force is always perpendicular to velocity of the particle.