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1+cos^2 2theta=2(cos^4 theta+sin^4 theta...

`1+cos^2 2theta=2(cos^4 theta+sin^4 theta)`

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Prove that: 1+cos^2 2theta=2(cos^4theta+sin^4theta)

Prove that 1+cos^2 2theta=2(cos^4theta+sin^4theta)

Prove that: 1+cos^(2)2 theta=2(cos^(4)theta+sin^(4)theta)

The value of (1-2 sin^2 theta cos^2 theta )/(sin^4 theta +cos^4 theta )-1 is: (1-2 sin^2 theta cos^2 theta )/(sin^4 theta +cos^4 theta )-1 का मान है :

The value of (2(sin^6 theta+cos^6 theta)-3(sin^4 theta+cos^4 theta))/ (cos^4 theta-sin^4 theta-2cos^2 theta) is (2(sin^6 theta+cos^6 theta)-3(sin^4 theta+cos^4 theta))/ (cos^4 theta-sin^4 theta-2cos^2 theta) का मान है:

If |(1+sin^2 theta,sin^2 theta,sin^2 theta),(cos^2 theta,1+cos^2 theta,cos^2 theta),(4sin 4 theta,4sin4theta,1+4sin4theta)|=0, then ... sin 4theta equal to ....

sin^2theta+cos^4theta=cos^2theta+sin^4theta

If cos^2 theta-sin^2 theta= 1/2 then cos^4 theta-sin^4 theta=?

If u = (1 + cos theta) (1+ cos2 theta) - sin theta sin 2theta, v = sin theta (1 + cos2 theta) + sin 2 theta(1 + cos theta), "show that" u^(2) + v^(2) = 4(1 + cos theta) (1 + cos 2theta).

Prove the following identity : cos^4 theta- sin^4 theta= cos^2 theta-sin^2 theta= 2 cos^2 theta-1=1-2 sin^2 theta .