The following equation gives a relation between the mass `m_(1)` kept on a surface of area A and the pressure p exerted on this area.
`p((m_(1)+m_(2)x))/(A)`
What must be the dimensions of the quatities x and `m_(2)`?

(a) Define pressure . ( b) What is the relation between pressure force and area ? ( c) Calculate the pressure when a force of 200 N is exerted on an are of : 10m^(2) 5m^(2)

A box of mass 10 kg has a base area of 1m^(2) . What is the pressure exerted by it on the ground? (Take 1kg wt=10N)

The dimensions of a cubois are in the ratio of 1:2:3 and its total surface area is 198m^2 . Find the dimensions.

The dimensions of a cuboid are in the ratio of 1:2:3: and its total surface area is 88m^(2). Find the dimensions.

The dimensions of a cuboid are in the ratio of 1:2:3 and its total surface area is 88m^(2). Find the dimensions.

The dimensions of a cuboid are in the ratio 5:3:1 and its total surface area is 414\ m^2dot Find the dimensions.

The dimensions of a cuboid are in the ratio 5:3:1 and its total surface area is 414\ m^2dot Find the dimensions.

Assertion : Mass of solid floating in liquid is m_(1) and mass of liquid is m_(2) . Base area is A. Then pressure at bottom is p_(0) + ((m_(1)+m_(2))g)/(A) Reason : Upward force on liquid from base of vessel is pA, where p is pressure at bottom.