For a common emitter transistor working in active state, following data is given `R_(L)=1KOmega` `V_("in")=10mV`
`triangleI_(B)=15muA,triangleI_(C)=3mA`. The input resistance `r_(i)`& voltage gain `A_(V)` for the transitor is

In a transistor connected in a common emitter mode it has, R_(c)=4kOmega, R_(i)=1kOmega, I_(c)=1mA and I_(b)= 20 muA. Find the voltage gain.

In a transistor connected in a common emitter mode it has, R_(c)=4kOmega, R_(i)=1kOmega, I_(c)=1mA and I_(b)= 20 muA. Find the voltage gain.

In a transistor, connected in common emitter mode R_(0)=5kOmega," "R_(i)=1kOmega," "I_(C)=1mA,I_(B)=40muA . Find the voltage gain.

A transistor, connected in common emitter configuration, has input resistance R_(i)=2kOmega and load resistance 6kOmega . If beta=60 and an input signal 10mV is applied, calculate the (i) resistance gain, (ii) voltage gain (iii) the power gain and (iv) the value of the output signal.

In a common emitter configuration with suitable bias, it is given that R_(L) is the load resistance and R_(BE) is small signal dynamic resistance (input side). Then, voltage gain, current gain and power gain are given , respectively, by : beta is current gain , I_(B), I_(C) and I_(E) are respectively base, collector and emitter currents.

For a common emitter transistor amplifier, the audio signal voltage across the collector resistance (R_(c)) of 2 kOmega is 2 V. If the current amplification factor ( beta ) of the transistor is 100, calculate the input signal voltage (V_(BE)) and base current (I_(g)) for base resistance of 1 kOmega .

In a common emitter transistor amplifier the audio signal voltage across the collector is 3 V . The resistance of collector is 3 kOmega . If current gain is 100 and the base resistance is 2 kOmega , the voltage and power gain of the amlifier is :