`a,b,c` are sides of the triangle and `s` be its semi perimeter and `(s-a)=90, (s-b)=50` and `(s-c)=10` then find the area of the triangle

(b) The two sides of a triangle are 68 m and 75 m and its semi-perimeter is 110 m. Then find the area of the triangle.

If in a triangle with sides a, b & c, (s-a)=5cm,(s-b)=10cm&(s-c)=1cm find area of the triangle.

If a,b,c are the sides of a triangle and s=(a+b+c)/2 , prove that 8(s-a)(s-b)(s-c)leabc .

If a,b,c are the sides of a triangle and s=(a+b+c)/(2), then prove that 8(s-a)(s-b)(s-c)<=abc

If (s-a)=5cm (s-b)=10cm (s-c)=1cm , find a,b & c Where a,b & c are sides of the triangle.

If bar(a), bar(b), bar(c ) are the sides and s is the semi perimeter of the tirangle ABC then the area of the triangle Delta = sqrt(s(s-a) (s-b) (s-c))

The semi-perimeter of a triangle is 132 cm .The product of the difference of semi-perimeter and its respective sides is 13200cm^(3) .Find the area of the triangle

If s is the semi-perimeter of DeltaABC and if (s-a)/4=(s-b)/5=(s-c)/6,"then "sumsin^(2)(A/2)=

If in a triangle ABC, (s-a)(s-b)= s(s-c), then angle C is equal to