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A urn contains m white and n black balls...

A urn contains m white and n black balls. Balls are drawn one by one till all the balls are drawn. Probability that the second drawn ball is white is

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given that no of white balls = m
no of black balls = n
total no of balls = `m+n`
probability of 2nd ball is white:
1st case: (w,w)
`P= m/(m+n) * (m-1)/(m+n-1)` eqn(1)
case 2 : (b, w)
`n/(m+n)*m/(m+n-1)` eqn (2)
...
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