A particle is projected from horizontal ground at angle `'theta'` with speed 'u'. In same plane of motion a horizontal acceleration 'a' exists so that projected particle returns back to point of projection. Find time of flight.

A particle is projected from the ground with an initial speed of 5 m s^(-1) at an angle of projection 60° with horizontal. The average velocity of the particle between its time of projection and the time it reaches highest point of trajectory

A particle is projected from ground with speed u and at an angle theta with horizontal. If at maximum height from ground, the speed of particle is 1//2 times of its initial velocity of projection, then find its maximum height attained.

A particle is projected from ground with speed u and at an angle theta with horizontal. If at maximum height from ground, the speed of particle is 1//2 times of its initial velocity of projection, then find its maximum height attained.