`(4)/(3)times(4)/(3)`

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((-4)/(3))times(1)/(2)+((-4)/(3))times((-7)/(5))

(9)/(8)times(4)/(3)-:(3)/(4)times(2)/(3)=

[((3)/(4))^(3)]-:((3)/(4))^(2)times((1)/(3))^(-2)times3^(-1)times((1)/(6))^(-1)

((4)/(3))^(-4)times((4)/(3))^(-5)=((4)/(3))^(3x)

(3)/(4)+(3)/(4)times2+(3)/(2)

((2)/(11))^(4)times((4)/(3))^(2)times((3)/(2))^(3)

Find the value of x so that ((3)/(4))^(-9)times((3)/(4))^(-7)=((3)/(4))^(4x)

(2^(2)times3^(4)times4)/(3times32),

((-4)/3)^2 xx ((-4)/3)^8 xx ((-4)/3)^(-10)

Simplify and write the in the exponential form: ((2^(4))^(5)xx(3^(3))^(4))/((2^(3))^(4)xx(3^(2))^(3))