The velocity of a projectile at the initial point A is `(2 hati +3 hatj) ms^(-1)`. Its velocity (in `ms^(-1))` at point B is

The velocity of a projectile at the initial point A is (2 hati +3 hatj)m//s . Its velocity (in m//s) at point B :

The velocity of a projectile at the initial point A is (2hati+3hatj) m//s . Its velocity (in m/s) at point B is

The velocity of a projectile at the initial point A is (2hati+3hatj) m//s . Its velocity (in m/s) at point B is

The velocity of a projectile at the initial point A is (2hati+3hatj) m//s . Its velocity (in m/s) at point B is

The velocity of a projectile at the initial point A is (2hati+3hatj)m/s. It's velocity (in m/s) at point B is -

The velocity of a projectile at the initial point A is (2hat(i)+3hat(j))m//s .Its velocity (in m//s) at point B is

The velocity of a projectile at the initial point A is (2 i+3 j)m/s .Its velocity (in m/s ) at point B is

The initial velocity of a projectile at the point of projection is 3hat i+4hat j ms^(-1) .Then the velocity of striking on the ground is

The velocity of projectile at the point of projection is 2hati + 3hatj m//s . The velocity at a point where the projectile reaches is