the value of `3^[1/(sqrt2+1)+1/(sqrt3+sqrt2)+1/(sqrt4+sqrt3)+...........+1/(sqrt16+sqrt15)]` is

1/(sqrt3 + sqrt2) + 1/(sqrt3 -sqrt2)=

Value of 1/(sqrt2+1)+1/(sqrt3+sqrt2)+1/(sqrt4+sqrt3)+....+1/(sqrt100+sqrt99) is

The value of (1-sqrt2) + (sqrt2-sqrt3)+(sqrt3-sqrt4)+ ............ + (sqrt15-sqrt16) is

The value of { 1/(sqrt6 - sqrt5) - 1/(sqrt5 - sqrt4) + 1/(sqrt4 - sqrt3) - 1/(sqrt3 - sqrt2) + 1/(sqrt2 - 1)} is :

Simplify: (1)/(sqrt2 +1) + (1)/(sqrt3 + sqrt2) + (1)/(sqrt4 + sqrt3)

Find the value of: 1/(1+sqrt2)+1/(sqrt2+sqrt3)+1/(sqrt3+sqrt4)+...1/(sqrt99+sqrt100)

1/(1-sqrt(2))+ 1/(sqrt(2)-sqrt(3))+1/(sqrt(3)-sqrt(4))+..........+1/(sqrt(8)-sqrt(9))