(a) `2(1)/(5)` from 5 (b) `(5)/(24)` from `(9)/(12)`

Subtract : (i) (3)/(4) from (1)/(3) (ii) (-5)/(6) from (1)/(3) (iii) (-8)/(9) from (-3)/(5) (iv) (-9)/(7) from -1 (v) (-18)/(11)from1 (vi) (-13)/(9) from0 (vii) (32)/(13) from (-6)/(5) (viii) -7 from (-4)/(7) (ix) (5)/(9) from (-2)/(3) (x) 5 from (-3)/(5)

Subtract 3(5)/(9) from 5(1)/(6)

Subtract the sum of 3(5)/(9) and 3(1)/(3) from the sum of 5(5)/(6) and 4(1)/(9)

Solve 1(4)/(5)+20-280-:25=?8(1)/(5)(b)9(1)/(2) (c) 11(1)/(2) (d) 10(3)/(5) (e) 12(1)/(5)

Evaluate: b. 5 (5)/(11) - 1 (5)/(12) - 2 (7)/( 24)

A (-1,4),B[1,-4) and C(5,4) are the vertices of a triangle.Then,the length of the altitude from A onto BC is (A) (12)/(5) (B) (12)/(sqrt(5)) (C) (12)/(5sqrt(5)) (D)3

The sum and product of the slopes of the tangents to the hyperbola (x^(2))/(4)-(y^(2))/(2)=1 drawn from the point (3,-2) are (A)-(12)/(5),(6)/(5)(B)(12)/(5),(6)/(5)(C)(11)/(4),(7)/(5)(D)-(12)/(5),(8)/(5)

Simplify : (i) (-2)/3+5/9-(-7)/6 (ii) 5/(12)+(-5)/(18)-7/(24)

Simplify : (i) (-2)/3+5/9-(-7)/6 (ii) 5/(12)+(-5)/(18)-7/(24)

Take out 5.746 from 9.1.