A particle moves on a line according to the law `s=at^(2)+bt+c`. If the displacement after 1 sec is 16 cm, the velocity after 2 sec is 24 cm/sec and acceleration is `8cm//sec^(2)`, then

A particle moves on a line according to the law s=at^2+bt+c . If the displacement after one second is 16 cm, the velocity after 2 second is 24 cm/sec and the acceleration is 8 cm/ sec^2 , then (a,b,c)=

A particle moves on a line according to the law s = at^(2) + bt + c . If the displacement after one second is 16 cm, the velocity after 2 second is 24 cm/sec and the acceleration is 8cm//sec^(2) . Then (a,b,c)

The equation of motion of particle is S=at^(2) +bt+c .If the displcement after 1 sec is 20 m, velo0city after 2 sec is 30 m/ sec and the acceleration is 10m//se^(2) , then

A particle moves along a straight line according to the law of motion S = at^2+bt+c if at end of 3 seconds, it has covered 20 cms, attained velocity 9cm//sec and has acceleration 4cm//sec^2 , find a,b,c.

In the above example, the velocity after 2 sec will be - (in m/sec)

A particle is moving along a line according s= f(t) = 8t + t^3 . Find acceleration at t = 2 sec.

A body moves according to the formula v=l+t^2 , where V is the velocity at time t. The acceleration after 3sec will be ( v in cm//sec )

The velocity v m/sec of particle is proportional to the cube of the time. If the velocity after 2 secs is 4m/sec, then v is equal to :