The temperatures of two bodies A and B are `727^(@)C` and `127^(@)C` . The ratio of rate of emission of radiations will be

The temperature of two bodies A and B are respectively 727^(@)C and 327^(@)C . The ratio H_(A) : H_(B) of the rates of heat radiated by them is

The temperature of two bodies A and B are respectively 727^(@)C and 327^(@)C . The ratio H_(A) : H_(B) of the rates of heat radiated by them is

Two bodies A and B are kept in an evacuated chamber at 27^@C . The temperatures of A and B are 327^@ and 427^@C and respectively. The ratio of rates of loss of heat from A and B will be–

Temperature of substances A and B are 727^(@)C and 327^(@)C respectively, then ratio of rate of their radiant energy H_(A):H_(B)= . . . . .

A black body is heated from 27^(@)C to 127^(@)C . The ratio of their energies of radiation emitted will be

The temperature of a body in increased from 27^(@)C to 127^(@)C . By what factor would the radiation emitted by it increase?

The temperature of a body in increased from 27^(@)C to 127^(@)C . By what factor would the radiation emitted by it increase?

Two bodies are at temperature 27^(@) and 927^(@)C . The heat energy radiated by them will be in the ratio:

Two bodies hae temperatures as 227^(@)C and 727^(@)C ratio of heat radiated by them will be

The rate of emission of radiation of a black body at 273^(@)C is E , then the rate of emission of raidiation of this body at 0^(@)C will be