Statement-1 : When temperature of a black body is halved, wavelength corresponding to which energy radiate is maximum become twice.
Statement-2 : This is as per Wien's Law.

Statement-1 : As temperature of a black body is raised, wavelenght corresponding to which energy emitted is maximum, reduces. Statement-2 : Higher temperature would mean higher energy and hence higher wavelength.

If the temperature of a black body is increased then the wavelength corresponding to the maximum emission will

When the temperature of black body rises, then the wavelength corresponding to the maximum intensity (lamda_(m))

Statement I: As the temperature of the black body increases, the wavelength at which the spectral intensity (E_lamda) is maximum decreases. Statement II: The wavelength at which the spectral intensity will be maximum for a black body is proportional to the fourth power of its absolute temperature.

Statement I: As the temperature of the black body increases, the wavelength at which the spectral intensity (E_lamda) is maximum decreases. Statement II: The wavelength at which the spectral intensity will be maximum for a black body is proportional to the fourth power of its absolute temperature.

Statement-1 : When temperature of a black body is doubled, energy radiated/sec/area becomes 16 times. Statement-2 : This is per Stefan's law.

If the temperature of any ideal black body is halved, then the wavelength of maximum emission will be

If the temperature of any ideal black body is halved, then the wavelength of maximum emission will be

The temperature at which a black body ceases to radiate energy is .

The surface temperature of a hot body is 1227^(@)C . Find the wavelength at which it radiates maximum energy. Given Wien's constant = 2898 cm K .