The temperature at which a black body of unit area loses its energy at the rate of 1 joule/second is

The temperature at which a black body ceases to radiate energy is .

A black body radiates energy at the rate of 1 xx 10 J // s xx m at temperature of 227 ^(@)C , The temperature to which it must be heated so that it radiates energy at rate of 1 xx 10 J//sm , is

What is the temperature at which a black body radiates heat at the rate of one kilowatt per unit area ? (Stefan 's constant sigma = 5.7 xx 10^(-8) S.Iunits)

The original temperature of a black body is . 727^(@) C . The temperature at which this black body must be raised so as to double the total radiant energy, is

Calculate temperature at perfectly black body radiates energy at the rate 5.67 xx 10^4 W/m^2 .

The rate at which a black body emits radiation at a temperature T is proportional to

At temperature 27^(@)C, black body is emitting at heat at a rate of 3.0 xx 10^(5) Joule/second- "metre"^(2) At what temperature will it emit heat at rate of 243 xx 10^(5) Joule/second-metre)?

Find the surface area of black body maintained at 127^@C radiating energy at the rate of 1459.2 J//sec .

The energy emitted per second by a black body at 27^(@)C is 10 J. If the temperature of the black body is increased to 327^(@)C , the energy emitted per second will be