ABC is a triangle whose medians AD and BE are perpendicular to each other. If `AD=p` and `BE = q` then area of `triangleABC` is

ABC is a triangle whose medians AD and BE are perpendicular to each other.If AD=p and BE=q then area of /_ABC is

ABC is a triangle whose medians AD and BC are perpendicular to each other.If AD=p and BE=q then area of /_ABC is

In a triangle ABC, medians AD and BE are drawn . If AD=4 , /_DAB=(pi)/(6) and /_ABE=(pi)/(3) , then the area of the DeltaABC is

In a triangle ABC, medians AD and CE are drawn. If AD=5, angle DAC=pi/8 and angle ACE=pi/4 then the area of the triangle ABC is equal to (5a)/b, then a+b is equal to

In a triangle ABC, medians AD and CE are drawn.If AD=5,/_DAC=(pi)/(8) and /_ACE=(pi)/(4) then the area of the triangle ABC is equal to (5a)/(b), then a+b is equal to

In a Delta ABC , the median AD is perpendicular to AC. If b = 5 and c = 11, then a =

In a Delta ABC , the median AD is perpendicular to AC. If b = 5 and c = 11, then a =

In triangle ABC, medians AD and CE are drawn AD = 5, angle DAC = pi//8, and angle ACE = pi//4 , then the area of the triangle ABC is equal to

The median AD of a Delta ABC is perpendicular to AB,prove that tan A+2tan B=0