Home
Class 11
MATHS
P is a point ony^2=4ax lying in the firs...

P is a point on`y^2=4ax` lying in the first quadrant and on the arc OL, where O (0,0) is the vertex M is the foot of the perpendicular from F (the focus) to the tangent at P Find the maximum area of triangle FMP (L is an extremity of the latus rectum)

Promotional Banner

Similar Questions

Explore conceptually related problems

If M is the foot of the perpendicular from a point P on a parabola to its directix and SPM is an equilateral triangle where S is the focus then SP=

Prove that the locus of the foot of the perpendicular drawn from the focus of the parabola y ^(2) = 4 ax upon any tangent to its is the tangent at the vertex.

The straight line joining any point P on the parabolay ^(2)=4ax to the vertex and perpendicular from the focus to the tangent at Pintersect at R, then the equation of the locus of R is

If 0 is the vertex and L,L' are the extremities of the latusrectum of the parabola y^(2)=4ax then the area of the triangle OLL' is

M is the foot of the perpendicular from a point P on a parabola y^(2)=4ax to its directrix and SPM is an equilateral triangle,where S is the focus.Then find SP.

Let Q be the foot of the perpendicular from the origin O to the tangent at a point P(alpha, beta) on the parabola y^(2)=4ax and S be the focus of the parabola , then (OQ)^(2) (SP) is equal to

M is the foot of the perpendicular from a point P on a parabola y^2=4a x to its directrix and S P M is an equilateral triangle, where S is the focus. Then find S P .