The coordinate of a moving point at time t are given by x = a ( 2t + sin 2t) , y = a ( 1-cos 2t). Prove that acceleration is constant.

The coordinate of a moving point at time t are given by x=a(2t+sin2t),y=a(1-cos2t) Prove that acceleration is constant.

The coordinates of a moving particle at any time t are given by, x = 2t^(3) and y = 3t^(3) . Acceleration of the particle is given by

The coordinates of a moving particle at any time t are given by, x = 2t^(3) and y = 3t^(3) . Acceleration of the particle is given by

x = "sin" t, y = "cos" 2t

x = "sin" t, y = "cos" 2t

The position of a point in time 't' is given by x = 1 + 2t + 3t^(2) and y = 2 - 3t + 4t^(2) . Then its acceleration at time 't' is

The x and y coordinates of a particle at any time t are given by x=7t+4t^2 and y=5t , where x and t is seconds. The acceleration of particle at t=5 s is

The x and y coordinates of a particle at any time t are given by x=7t+4t^2 and y=5t , where x and t is seconds. The acceleration of particle at t=5 s is

The x and y coordinates of a particle at any time t are given by x=7t+4t^2 and y=5t , where x and t is seconds. The acceleration of particle at t=5 s is

The x and y coordinates of a particle at any time t are given by x=7t+4t^2 and y=5t , where x and t is seconds. The acceleration of particle at t=5 s is