[" The area enclosed between the curves "],[y=ln(x+e),x=ln((1)/(y))" and "x" -axis in square units is "]

The area enclosed between the curves y=(log)_e(x+e),x=(log)_e(1/y), and the x-axis is 2s qdotu n i t s (b) 1s qdotu n i t s 4s qdotu n i t s (d) none of these

Find the area enclosed between the curves: y=log_(e)(x+e),x=log_(e)((1)/(y))& the x -axis.

The area enclosed between the curve y= log_(e)(x+e) and the coordinate axes ( in square unit) is-

The area encosed between the curves y=log_(e)(x+e),y=e^(x) and the X-axis is

The area enclosed between the curve y=log_(e)(x+e) and the co-ordinate axes is

The area enclosed between the curve y = log_e (x +e ) and the coordinate axes is

The area enclosed between the curve y=log_(e)(x+e) and the coordinate axes is

The area enclosed between the curve y=log_(e)(x+e) and the coordinate axes is