" 24."sec^(-1)(tan2x)

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sec^(2)2x=1-tan2x

Solve the equation sec ^(2)2x=1-tan2x

Find the general solution of the following equations : sec^(2)2x=1-tan2x

Find the general solution : quad sec^(2)2x=1-tan2x

If tan y = (tan x+sec x-1)/(tanx -sec x+1) show that (dy)/(dx) = 1/2

If tan y=(tan x+sec x-1)/(tan x-sec x+1) show that (dy)/(dx)=(1)/(2)

If tan y=(tan x+sec x-1)/(tan x-sec x+1), " show that, " (dy)/(dx)=(1)/(2) .

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f((2tan x)/(1+tan^(2)x))=((cos2x+1)(sec^(2)x+tan x))/(2) then f(x)=