If `sintheta+costheta=m` then prove that `sin^6theta+cos^6theta=(4-3(m^2-1)^2)/4` where `m^2<=2`

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If sintheta+costheta=m , then prove that sin^6theta+cos^6theta=(4-3(m^2-1)^2)/4,\ w h e r e\ m^2lt=2.

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