`(q)/(4)+7=5`

If p/q = 5/7 then (3p)/(4q) =square

Express each of the rational number of the form (p)/(q):(-7)/(4)+(5)/(3)+(-1)/(2)+(-5)/(6)+2

Simplify each of the following and write as a rational number of the form (p)/(q):(3)/(4)+(5)/(6)+(-7)/(8)( ii) (2)/(3)+(-5)/(6)+(-7)/(9)

int(dx)/(sqrt(x+7)-root(4)(x+7))=P sqrt(x+7)+Q(x+7)^((1)/(4))+R ln|(x+7)^((1)/(4))-1|+ then (A)P!=Q!=R(B)Q=R(C)P!=Q(D)P+Q+R=10

Simplify and Express them into rational number of the form p/q : ((-2)/7)^(4)*((-7)/5)^2

Express each of the rational number of the form p/q : ((-2)/7)^(-4)x\ ((-7)/5)^2

Let the polynomials be (1) -13q^(5) + 4q^(2) + 12q (2) (x^(2) + 4 ) ( x^(2) + 9) (3) 4q^(8) - q^(6) + q^(2) (4) - ( 5)/( 7) y^(12) + y^(3) + y^(5) Then ascending order of their degree is

Find the products: (7p^4+q)(49 p^8-7p^4q+q^2)

If (7x+4y) : (7x-4y) ::(7p+4q):(7p-4q) , there show that x , y, p and q are in proportion.