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If tantheta=a/b , show that (asintheta-b...

If `tantheta=a/b` , show that `(asintheta-bcostheta)/(asintheta+bcostheta)=(a^2-b^2)/(a^2+b^2)`

Answer

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If tan theta =a/b ,show that (asintheta-bcostheta)/(asintheta+bcostheta)=(a^2-b^2)/(a^2+b^2)

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Knowledge Check

  • If btantheta=a , the value of (asintheta-bcostheta)/(asintheta+bcostheta) (a) (a-b)/(a^2+b^2) (b) (a+b)/(a^2+b^2) (c) (a^2+b^2)/(a^2-b^2) (d) (a^2-b^2)/(a^2+b^2)

    A
    `(a-b)/(a^2+b^2)`
    B
    `(a+b)/(a^2+b^2)`
    C
    `(a^2+b^2)/(a^2-b^2)`
    D
    `(a^2-b^2)/(a^2+b^2)`

  • If x=(acostheta+bcostheta)/(a+b), then

    A
    `x` has the same dimensions as `a` and `b`
    B
    `a` and `b` have different dimensions
    C
    `x` has no dimensions
    D
    `x` has dimensions of wavelength.

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