[" 9.For "a in R" (the set of all real numbers),"a!=-1" ,"],[lim((1^(a)+2^(a)+...+n^(a)))/(n rarr oo)((n+1)^(a-1)[(na+1)+(na+2)+...+(na+n)])/(" Then "a=)=(1)/(60)" ."]

For a epsilonR (the set of all real numbers) a!=-1, lim_(n to oo) ((1^(a)+2^(a)+………+n^(a)))/((n+1)^(a-1)[(na+1)+(na+2)+………..+(na+n)])=1/60 Then a=

For a epsilonR (the set of all real numbers) a!=-1 , lim_(n to oo) ((1^(a)+2^(a)+………+n^(a)))/((n+1)^(a-1)[(na+1)+(n+2)+………..+(na+n)])=1/60 Then a=

For a in RR (the set of all real numbers), a ne-1,underset(n to oo)lim(1^(a)+2^(a)+…+n^(a))/((n+1)^(a-1)[(na+1)+(na+2)+…+(na+n)])=(1)/(60) Then a =

For a in R (the set of all real numbers),a!=-1)(lim)_(n rarr oo)((1^(a)+2^(a)++n^(a))/((n+1)^(a-1)[(na+1)+(na+2)+......(na+n)])=(1)/(60) Then a=(a)5 (b) 7(c)(-15)/(2) (d) (-17)/(2)

For a in R (the set of all real numbers), a!=-1), (lim)_(n->oo)((1^a+2^a++n^a)/((n+1)^(a-1)[(n a+1)+(n a+2)+......(n a+n)])=1/(60.) Then a= (a) 5 (b) 7 (c) (-15)/2 (d) (-17)/2

lim_(n rarr oo)2^(1/n)

lim_(n rarr oo)((-1)^(n)n)/(n+1)

lim_(n rarr oo)(2^(n)+3^(n))^(1/n)