" Find the roots "alpha,beta,gamma" of "x^(3)-11x^(2)+36x-36=0" if "(2)/(beta)=(1)/(alpha)+(1)/(gamma)

If alpha, beta ,gamma are the roots of 2x^(3) - 5x^(2) + 3x - 1 = 0 then (1)/(alpha beta ) + (1)/(beta gamma) + (1)/(gamma alpha) =

If alpha,beta,gamma are the roots of the equation 2x^(3)-5x^(2)+3x-1=0, then (1)/(alpha beta)+(1)/(beta gamma)+(1)/(gamma alpha) is

If alpha,beta,gamma are the roots of x^(3)+2x^(2)-3x-1=0 then alpha^(-2)+beta^(-2)+gamma^(-2)=

If alpha,beta,gamma are the roots of x^(3)+2x^(2)+3x+8=0 then (alpha+beta)(beta+gamma)(gamma+alpha)=

if alpha, beta, gamma are roots of x^3-3x^2+3x+7=0 , then find (alpha-1)/(beta-1)+(beta-1)/(gamma-1)+(gamma-1)/(alpha-1)

If alpha , beta , gamma are the roots of x^3 -6x -4=0 then the equation whose roots are (beta gamma +(1)/( alpha)) ,(gamma alpha +(1)/(beta)) , (alpha beta +(1)/( gamma)) is

if alpha,beta,gamma are the roots of x^3-3x^2 +3x + 7 =0 then (alpha-1)/(beta-1)+(beta-1)/(gamma-1)+(gamma-1)/(alpha-1)

if alpha,beta,gamma are the roots of x^3-3x^2 +3x + 7 =0 then (alpha-1)/(beta-1)+(beta-1)/(gamma-1)+(gamma-1)/(alpha-1)

if alpha,beta,gamma are the roots of x^3-3x^2 +3x + 7 =0 then (alpha-1)/(beta-1)+(beta-1)/(gamma-1)+(gamma-1)/(alpha-1)

if alpha,beta,gamma are the roots of x^3-3x^2 +3x + 7 =0 then (alpha-1)/(beta-1)+(beta-1)/(gamma-1)+(gamma-1)/(alpha-1)