The time period of a bar magnet oscillating in a uniform magnetic field is 3 seconds. if the magnet is cut into two equal parts along the equatorial line of the magnet and one part is made to vibrate in the same field, what is the time period ?

What is the time period of a bar magnet oscillating in uniform magnetic field ? Explain the terms involved.

The time period of a thin bar magnet in earth's magnetic field is T. If the magnet is cut into two equal parts perpendicular to its lengh, the time period of each part in the same field will be

What is the magnetic field along the axis and equatorial line of a bar magnet ?

The time period of a bar magnet in uniform magnetic field vec(B) is 'T'. It is cut into two halves, by cutting it parallel to its length then the time period of each part in same field is

The time period of a freely suspended bar magnet in a field is 2s. It is cut into two equal parts along its axis, then the time period is

The time period of a freely suspended bar magnet in a field is 2s. It is cut into two equal parts along its axis, then the time period is

The period of oscillation of a freely suspended bar magnet is 4 second. If it is cut into two equal parts length wise then the time period of each part will be

A thin rectangular magnet suspended freely has a period of oscillation T in a uniform magnetic field . Now it is broken in two equal parts perpendicular to magnetic axis and one place is allowed to oscillate in the same field . If its period of oscillation is T' , then ration (T)/(T') is