100 " mL of " 0.01 M `KMnO_(4)` oxidised 100 mL `H_(2)O_(2)` in acidic medium. The volume of same `KMnO_(4)` required in strong alkaline medium to oxidise 100 " mL of " same `H_(2)O_(2)` will be:

200 ml of 0.01 M KMnO_(4) oxidise 20 ml of H_(2)O_(2) sample in acidic medium. The volume strength of H_(2)O_(2) is

200 ml of 0.01 M KMnO_(4) oxidise 20 ml of H_(2)O_(2) sample in acidic medium. The volume strength of H_(2)O_(2) is

100mL of 1M KMnO_(4) oxidised 100mL of H_(2)O_(2) in acidic medium ( when MnO_(4)^(-) is reduced to Mn^(2+) ) , voluem of same KMnO_(4) required to oxidise 100mL of H_(2)O_(2) in basic medium ( when MnO_(4)^(-) is reduced to MnO_(2) ) will be :

100 mL of 0.01M KMnO_4 oxidises 100mL of acidified H_2O_2 . The volume of Oxygen in (MnO_4^(-)) changes to Mn^(2+) in acidic medium and to MnO_4 in alkaline medium).

What volume of 0.1 M KMnO_4 is required to oxidise 100 " mL of " 0.2 M FeSO_4 in acidic medium ? The reaction involved is