If a funciton `f:[2,oo] to B` defined by `f(x)=x^(2)-4x+5` is a bijection, then B=

If f: [2, oo) rarr B defined by f(x)=x^(2)-4x+5 is a bijection, then B=

If f:[2, oo)rarrB defined by f(x)=x^(2)-4x+5 is a bijection, then B=

If f: [2,infty) to B defined by f(x) =x^(2)-4x+5 is a bijection, then B=

If a functions f: [2,oo) rarr B defined by f(x) = x^2 - 4x + 5 is a bijection, then B is equal to a)R b) [1,oo) c) [4,oo) d) [5,oo)

If a function f:[2,oo)toR is defined by f(x)=x^(2)-4x+5 , then the range of f is

f:(-1,1) to B defined by f(x)=tan^(-1)((2x)/(1-x^(2))) is bijection then B =

The function f: A->B defined by f(x)=-x^2+6x-8 is a bijection, if A=(-oo,\ 3] and B=(-oo,\ 1] (b) A=[-3,\ oo) and B=(-oo,\ 1] (c) A=(-oo,\ 3] and B=[1,\ oo) (d) A=[3,\ oo) and B=[1,\ oo)

The function f: A->B defined by f(x)=-x^2+6x-8 is a bijection, if A=(-oo,\ 3] and B=(-oo,\ 1] (b) A=[-3,\ oo) and B=(-oo,\ 1] (c) A=(-oo,\ 3] and B=[1,\ oo) (d) A=[3,\ oo) and B=[1,\ oo)

If f: A->B given by 3^(f(x))+2^(-x)=4 is a bijection, then A