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Let /\ABC is (B+C)/11=(c+a)/12=(a+b)/12 ...

Let `/_\ABC` is `(B+C)/11=(c+a)/12=(a+b)/12` (where `AB=c,BC=a` and `AC=b)` and `(cosA)/alpha= (cosB)/beta` =(cosC)/gamma` then possible ordered triplet of `(alpha, beta, gamma)` is (A) `(9, 17, 25)` (B) `(19, 7, 25)` (C) `(7, 19, 25)` (D) `(19, 25, 7)`

A

(3,4,5)

B

(19,7,25)

C

(7,19,25)

D

(5,12,13)

Text Solution

Verified by Experts

The correct Answer is:
C
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