Find the digit at unti's place in the number `17^(1995)+11^(1995)`
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The sum of the digits of a two-digit number is 11. if 9 is subtracted from the number, then the digits interchagne their places. Find the number. The following steps are involved in solving the above problem. Arrange them in sequential order (A) Let the units digit be x. therefore , the tens digit is (11-x). therefore The number is 10(11-x)+x=110-9x . (B) Given that 110-9x-9=9x+11rArrx=5 . (C) Units digit is S and tens digit is 6 and the required number is 65. (D) The number formed by interchanging the digits is 10x+(11-x)=9x+11 .
A two digit number is such that the product of its digits is 12. When 9 is added to the number, the digits interchange their places, find the number :
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