For a particle displacement time relation is `t = sqrt(x) + 3`. Its displacement when its velocity is zero -

The displacement 'x' (in meter) of a particle of mass 'm' (in kg) moving in one dimension under the action of a force is released to time 't' (in sec) by t = sqrt(x) + 3 . The displacement of the particle when its velocity is zero will be.

The relation 3t=sqrt(3x)+6 describe the displacement of a particle in one direction where x is in metres and t in sec. The displacement, when velocity is zero is

The relation 3t=sqrt(3x)+6 describe the displacement of a particle in one direction where x is in metres and t in sec. The displacement, when velocity is zero is

The displacement ‘x’ (in meter)of a particle of mass ‘m’ (in kg) moving in one dimension under the action of a force, is related to time 't' (in sec) by t= sqrtx + 3 . The displacement of the particle when its velocity is zero will be:

The displacement 'x' (in meter) of a particle of mass 'm' (in kg) moving in one dimension under the action of a force is released to time 't' (in sec) by t^2 = sqrt(x) + 2 . The displacement of the particle when its velocity is zero will be.

The relation 3t=sqrt(3x)+6 describes the displacement of a particle in one" direction where "x" is in metres and t in sec.The displacement,when velocity is zero,is meters.