pi x+y=9

Factorize: x y^9-y x^9

9 taken away from the sum of x and y is x+y-9( b) 9-(x+y)(x+y)/(9) (d) (9)/(x+y)

x tan ( theta - (pi)/(6)) = y tan (theta + ( 2pi)/(3)) implies (x + y)/( x -y) =

The sum cos ((pi) / (9)) + cos ((2 pi) / (9)) + cos ((3 pi) / (9)) + ... + cos ((17 pi) / (9 )) =

Let y=g(x) be the solution of the differential equation sin x(dy)/(dx)+y cos x=4x, x in (0,pi) If y(pi/2)=0 , then y(pi/6) is equal to

Find the incentre of a triangle formed by the lines x "cos" (pi)/(9) + y "sin" (pi)/(9) = pi, x "cos" (8pi)/(9)+ y "sin" (8pi)/(9) = pi " and x "cos" (13pi)/(9) + y "sin" ((13pi)/(9)) = pi.