5.85g of NaCl is dissolved in 1L of pure water. The number of ions in 1ml of this solution is:

5.85g NaCl is dissolved in 1L water. The number of ions of Na^(+) and Cl^(-) in 1 ml of this solution will be

5.85 g NaCl is dissolved in 500 ml of water. The molarity is

(a) 5.85g of NaCl is dissolved in 200mL of water. What will be the molarity of this solution ? (b) Calculate the molarity of the solution obtained by dissolving 20.6g NaBr in 500mL of water.

If 5.85 g of NaCl is dissolved in 90g of water, the mole fraction of solute is

5.85 g of NaCl are dissolved in 90 g of water. The mole fraction of NaCl is-

5.85 g of NaCl are dissolved in 90 g of water. The mole fraction of NaCl is-

5.85 g of NaCl are dissolved in 90 g of water, the mole fraction of NaCl is :