" In a "Delta ABC,/_A=(2 pi)/(3),b-c=3sqrt(3)cm" and "ar(Delta ABC)=(9sqrt(3))/(2)cm^(2)." Then "a" is "

In a Delta ABC,A=(2 pi)/(3),b-c=3sqrt(3)cm and area(Delta ABC)=(9sqrt(3))/(2)cm^(2). Then a is

In DeltaABC, A = (2pi)/(3), b -c = 3 sqrt3 cm and " area of " Delta ABC = (9sqrt3)/(2) cm^(2) , then a =

In DeltaABC, A = (2pi)/(3), b -c = 3 sqrt3 cm and " area of " Delta ABC = (9sqrt3)/(2) cm^(2) , then BC =

In DeltaABC, A = (2pi)/(3), b -c = 3 sqrt3 cm and " area of " Delta ABC = (9sqrt3)/(2) cm^(2) , then BC =

If in Delta ABC, b-c = 3sqrt3 , A= 120 ^(@) and the area of Delta ABC = (9sqrt3)/( 2) sq. cm, then a=

In a Delta ABC,A=(pi)/(3) and b:c=2:3. If tan alpha=(sqrt(3))/(5),0

In Delta ABC angle A = (pi)/(6) & b:c= 2: sqrt(3) "then " angle B is

In A Delta ABC if ( sqrt(3)-1)a=2b, A=3B then c is

In a Delta ABC, a + b = 3 (1 + sqrt(3)) cm and a - b = 3 (1 - sqrt(3)) cm. If angle A is 30^(@) , then what is the angle B ?