" (b) "log(sin x)^(cos x)

If: (log_(cos x) sin x) + (log_(sin x)cos x)=2 , then, in general, x=

Integrate log(sin x)^(cos x)

int log(sin x)*cos xdx

lim_(x=0)(log_(sin x)cos x)/(log_(sin((x)/(2)))cos((x)/(2)))

Differentiate log((sin x)/(1+cos x)) with respect to x:

int( cos 2 x)/(sin x+cos x)^2 d x is equal to a) -1/(sin x+cos x)+C b) log |sin x+cos x|+C c) log |sin x-cos x|+C d) 1(sin x+cos x)^2

int(1)/(1+tan x)dx=(log)_(e)(x+sin x)+C(b)(log)_(e)(sin x+cos x)+C(c)2(sec^(2)x)/(2)+C(d)(1)/(2){x+log(sin x+cos x)}+C

The solution of the equation "log"_("cos"x) "sin" x + "log"_("sin"x) "cos" x = 2 is given by

The solution of the equation "log"_("cos"x) "sin" x + "log"_("sin"x) "cos" x = 2 is given by

If log_(cos x)sin x + log_(sin x)cos x=2 then x =